Kendall's tau of an Archimedean copula via its generator #
Nelsen, An Introduction to Copulas, second edition, Corollary 5.1.4: for an Archimedean
copula with generator φ,
τ_C = 1 + 4 ∫₀¹ φ(t) / φ'(t) dt.
We prove this for generators whose inverse generator ψ has a continuous derivative where it is
positive (BivariateGenerator.IsC1; strict and non-strict generators alike), in the form
τ_C = 1 + 4 ∫₀¹ φ(t) ψ'(φ(t)) dt (BivariateGenerator.IsC1.kendallTau_eq) and in Nelsen's
form with the derivative of the generator (BivariateGenerator.IsC1.kendallTau_eq_deriv).
As in Nelsen's proof, τ_C = 4 E[C(U, V)] − 1 with E[C(U, V)] = ∫₀¹ (1 − K_C(t)) dt
(layer-cake formula), and the Kendall distribution function K_C(t) = t − φ(t) / φ'(t) of
Copula.Archimedean.KendallDistribution (Nelsen, Theorem 4.3.4).
For the outer power φ^δ, δ ≥ 1 (Nelsen, Section 4.5, the family C_{φ^δ}), the integrand
scales by 1/δ, so τ_{φ^δ} = 1 + (τ_φ − 1) / δ
(BivariateGenerator.IsC1.kendallTau_outerPower).
Nelsen, Corollary 5.1.4: τ_C = 1 + 4 ∫₀¹ φ(t) ψ'(φ(t)) dt for a C¹ generator,
where φ(t) ψ'(φ(t)) = φ(t) / φ'(t).
Nelsen, Corollary 5.1.4 in its original form τ_C = 1 + 4 ∫₀¹ φ(t) / φ'(t) dt, with φ'
the derivative of the generator.
The outer power φ^δ of a C¹ generator is C¹, with
(ψ(s^{1/δ}))' = ψ'(s^{1/δ}) · s^{1/δ - 1} / δ.
The Kendall integrand φ ψ'(φ) of the outer power φ^δ is 1/δ times that of φ.
Kendall's tau of the outer power φ^δ: τ_{φ^δ} = 1 + (τ_φ − 1) / δ.