Kendall's tau of the Frank family in Debye form #
Nelsen, An Introduction to Copulas, second edition, Example 5.4 / Table 4.1 (family 4.2.5):
for Frank's family with parameter θ > 0,
τ_θ = 1 − (4/θ) (1 − D₁(θ)), where D₁(θ) = (1/θ) ∫₀^θ t / (e^t − 1) dt is the Debye function of
order one (debyeOne).
kendallTau_frank (Corollary 5.1.4) gives
τ = 1 + (4/θ) ∫₀¹ (e^{θt} − 1) log((1 − e^{−θt}) / (1 − e^{−θ})) dt. After the substitution
x = θ t, an integration by parts against F(x) = e^x − 1 − x (with the boundary term at 0
vanishing because F(x) ≤ x (e^x − 1) and |w log w| ≤ 1) turns this into
∫₀^θ (e^x − 1) log(...) dx = −θ + ∫₀^θ x / (e^x − 1) dx (frank_integral_eq_debye), which is
the Debye form (kendallTau_frank_debye).
For θ < 0 (frankNegative θ, the reflection of Frank's copula with parameter −θ), the same
formula holds (kendallTau_frankNegative_debye), by τ(C^{σ₂}) = −τ(C) and the reflection
identity D₁(−x) = D₁(x) + x/2 (debyeOne_neg).
The key identity:
∫₀^θ (e^x − 1) log((1 − e^{−x}) / (1 − e^{−θ})) dx = −θ + ∫₀^θ x/(e^x − 1) dx.
The integrand t/(e^t − 1) of the Debye function is interval integrable on [0, x].
Nelsen, Example 5.4 / Table 4.1 (family 4.2.5) for negative parameters: Kendall's tau of
Frank's copula frankNegative θ (θ < 0) is 1 − (4/θ) (1 − D₁(θ)).