Kendall's tau of extreme-value copulas #
For a Pickands dependence function A which is differentiable on (0,1),
τ(C_A) = 1 - ∫₀¹ (A(t) - t A'(t)) (A(t) + (1-t) A'(t)) / A(t)² dt
(kendallTau_pickandsCopula),
and if moreover A is twice differentiable on (0,1) with integrable A'', integration by parts
gives the classical formula
τ(C_A) = ∫₀¹ t (1-t) A''(t) / A(t) dt (kendallTau_pickandsCopula_of_deriv2),
i.e. τ = ∫₀¹ t(1-t)/A(t) dA'(t).
Proof. By kendallTau_conditional_product, τ = 1 - 4 ∬ ∂₁C ∂₂C. For C_A the partial
derivatives are ∂₁C(u,v) = C(u,v) u⁻¹ (A(r) - r A'(r)) and
∂₂C(u,v) = C(u,v) v⁻¹ (A(r) + (1-r) A'(r)) with r = log v / log(uv); the conditional
distribution functions agree with them almost everywhere (conditionalCDF_eq_deriv, and the
transpose C_A^T = C_{A(1-·)}). The double integral is then computed with the same substitution
u = v^{1/t - 1} and Gamma integral as Spearman's rho (Copula.ExtremeValue.PickandsSpearman).
References: G. Gudendorf and J. Segers, Extreme-value copulas (2010); C. Genest and L.-P. Rivest, A characterization of Gumbel's family of extreme value distributions (1989); H. Joe, Dependence Modeling with Copulas (2014).
The transpose of C_A is the Pickands copula of t ↦ A(1 - t).
The ratio log y / log (x y), the Pickands coordinate of (x,y).
Instances For
Tangent-line bounds for a differentiable Pickands function: 0 ≤ A - tA' ≤ 1 and
0 ≤ A + (1-t)A' ≤ 1.
The derivative of the Pickands CDF in its first variable.
The CDF section of C_A has derivative ∂₁ C_A at interior points.
For each interior w, the conditional CDF of C_A is ∂₁ C_A(·, w) almost everywhere.
The integrand of Kendall's formula agrees a.e. with ∂₁C ∂₂C.
The product ∂₁C_A(x,y) ∂₂C_A(x,y), written with the first partial derivative of the
transposed copula.
Equations
- ProbabilityTheory.Copula.PickandsKendall.cross A x y = ProbabilityTheory.Copula.PickandsKendall.d1 A x y * ProbabilityTheory.Copula.PickandsKendall.d1 (fun (t : ℝ) => A (1 - t)) y x
Instances For
The double integral ∬ ∂₁C_A ∂₂C_A = ∫₀¹ (A - tA')(A + (1-t)A') / (4A²) dt.
Kendall's tau of a Pickands copula with A differentiable on (0,1):
τ(C_A) = 1 - ∫₀¹ (A(t) - t A'(t)) (A(t) + (1-t) A'(t)) / A(t)² dt.
A Pickands function is continuous on [0,1].
Kendall's tau of a Pickands copula (twice differentiable A):
τ(C_A) = ∫₀¹ t (1-t) A''(t) / A(t) dt, i.e. τ = ∫₀¹ t(1-t)/A(t) dA'(t).