Kendall's tau of the Raftery family #
For the Raftery copula C_θ (0 ≤ θ < 1, exponent p = 1/(1-θ), see
Copula.Families.Raftery) Kendall's tau is
τ(C_θ) = 2θ / (3 - θ) (kendallTau_raftery; Nelsen 2006, exercises of Ch. 5),
equivalently τ = 2(p-1)/(2p+1).
Proof. By kendallTau_conditional_product and exchangeability, τ = 1 - 4 ∬ ∂₁C ∂₂C. The
conditional distribution functions agree almost everywhere with the classical partial
derivatives (conditionalCDF_eq_deriv), which are explicit on both sides of the diagonal
(Raftery.condDeriv; the two branches meet continuously on the diagonal). Below the diagonal
(t ≤ x) the product of the partial derivatives is
∂₂C · ∂₁C = c(x) t^p/(2p-1) + p c(x) (x^p - x^{1-p}) t^{2p-1}/(2p-1)² with
c(x) = p x^{p-1} + (p-1) x^{-p}, whose integral over t ∈ [0,x] is elementary
(integral_partialProduct); above the diagonal the same integral appears after Fubini. Hence
∬ ∂₁C ∂₂C = 2 ∫₀¹ L = 3/(4(2p+1)).
References: A. E. Raftery, A continuous multivariate exponential distribution, Comm. Statist. A 13 (1984); R. B. Nelsen, An Introduction to Copulas (2006), exercises of Ch. 5 (Raftery family).
The product of the two partial derivatives below the diagonal.
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The integrand ∂₁C ∂₂C split along the diagonal.
An antiderivative of t ↦ ∂₂C(t,x) ∂₁C(t,x).
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- One or more equations did not get rendered due to their size.
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The closed form of ∫₀ˣ ∂₂C(t,x) ∂₁C(t,x) dt.
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∫₀ˣ ∂₂C(t,x) ∂₁C(t,x) dt = L(x).
∫₀¹ L = 3/(8(2p+1)).
The part of the integrand below the diagonal, as a function of (v, u).
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- ProbabilityTheory.Copula.RafteryKendall.lower p v u = if ↑u ≤ ↑v then ProbabilityTheory.Copula.RafteryKendall.partialProduct p ↑u ↑v else 0
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The part of the integrand above the diagonal, as a function of (v, u).
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- ProbabilityTheory.Copula.RafteryKendall.upper p v u = if ↑v < ↑u then ProbabilityTheory.Copula.RafteryKendall.partialProduct p ↑v ↑u else 0
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The conditional distribution function of the Raftery copula is the partial derivative
∂₁C_θ(u, v) = Raftery.condDeriv p v u (p = 1/(1-θ)) for almost every u.