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Papers.OrendayLaresRockel2026XiBeta.CompletionXi

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Equation (5.3): 1 - ξ(Q_A) = (3/2) J(w) #

The conditional distribution of V given U = u under Q_A puts mass p(u) at A(u) and 1 - p(u) at B(u); by (2.2) 1 - ξ = 6 ∬ h (1 - h), and integrating out the response first gives p (1 - p) (B - A) = p (1 - p) w. With w' = 1 - 2p this is (3/2) J(w).

The slope data d = 1 - 2p = w' of the gap function of a median section.

Equations
  • s.slopeData = { d := fun (u : ℝ) => 1 - 2 * s.p u, mono := ⋯, bdd := ⋯, integral_zero := ⋯ }
Instances For

    J(w) = ∫₀¹ w (1 - w'²) for the gap function of a median section.

    theorem Papers.OrendayLaresRockel2026XiBeta.MedianSection.kerR_mul_one_sub (s : MedianSection) {v t : ℝ} (ht0 : 0 ≤ t) (ht1 : t ≤ 1) :
    s.kerR v t * (1 - s.kerR v t) = s.p t * (1 - s.p t) * if s.A t ≤ v ∧ v < s.B t then 1 else 0

    The product form of the kernel: k (1 - k) = p (1 - p) 1{A ≤ v < B}.

    theorem Papers.OrendayLaresRockel2026XiBeta.MedianSection.integral_indicator_AB (s : MedianSection) {u : ℝ} (hu0 : 0 ≤ u) (hu1 : u ≤ 1) :
    (∫ (v : ↑unitInterval), if s.A u ≤ ↑v ∧ ↑v < s.B u then 1 else 0) = s.B u - s.A u

    Equation (5.3), first form: 1 - ξ(Q_A) = 6 ∫₀¹ p (1 - p) w.