Equation (5.3): 1 - ξ(Q_A) = (3/2) J(w) #
The conditional distribution of V given U = u under Q_A puts mass p(u) at A(u) and
1 - p(u) at B(u); by (2.2) 1 - ξ = 6 ∬ h (1 - h), and integrating out the response first
gives p (1 - p) (B - A) = p (1 - p) w. With w' = 1 - 2p this is (3/2) J(w).
theorem
Papers.OrendayLaresRockel2026XiBeta.MedianSection.measurable_kerR_uncurry
(s : MedianSection)
:
Measurable fun (z : ↑unitInterval × ↑unitInterval) => s.kerR ↑z.1 ↑z.2
theorem
Papers.OrendayLaresRockel2026XiBeta.MedianSection.integral_condCDF_sq_completion
(s : MedianSection)
(t : ↑unitInterval)
:
∫ (u : ↑unitInterval), s.completion.conditionalCDF u t ^ 2 = ∫ (u : ↑unitInterval), s.kernelCDF t u ^ 2
theorem
Papers.OrendayLaresRockel2026XiBeta.MedianSection.integrable_integral_kernelCDF_sq
(s : MedianSection)
:
MeasureTheory.Integrable (fun (t : ↑unitInterval) => ∫ (u : ↑unitInterval), s.kernelCDF t u ^ 2) MeasureTheory.volume
theorem
Papers.OrendayLaresRockel2026XiBeta.MedianSection.xi_completion_eq
(s : MedianSection)
:
s.completion.chatterjeeXi = (6 * ∫ (t : ↑unitInterval) (u : ↑unitInterval), s.kernelCDF t u ^ 2) - 2
Equation (5.3), first form: 1 - ξ(Q_A) = 6 ∫₀¹ p (1 - p) w.
theorem
Papers.OrendayLaresRockel2026XiBeta.MedianSection.one_sub_xi_completion
(s : MedianSection)
:
Equation (5.3): 1 - ξ(Q_A) = (3/2) J(w).