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Papers.OrendayLaresRockel2026XiBeta.RightSection

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The right-boundary median sections A_b and the copulas R_b (equation (5.5)) #

For b ∈ [0,1] the slope p_b equals 1 on [0, b/2], 1/2 on (b/2, 1 - b/2] and 0 afterwards, so that A_b(u) = min {u, (2u + b)/4, 1/2}. The two-branch copula of the source is R_b := Q_{A_b}, the maximal completion of A_b. Its gap function is w_b(u) = max {|u - 1/2|, (1 - b)/2}.

The slope of A_b: 1 on [0, b/2], 1/2 on (b/2, 1 - b/2], 0 afterwards.

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    theorem Papers.OrendayLaresRockel2026XiBeta.integral_eq_of_eq_on_Ioc {f : ℝ → ℝ} {c d k : ℝ} (hcd : c ≤ d) (h : ∀ t ∈ Set.Ioc c d, f t = k) :
    ∫ (t : ℝ) in c..d, f t = (d - c) * k
    theorem Papers.OrendayLaresRockel2026XiBeta.integral_rightSlope {b : ℝ} (hb : b ∈ Set.Icc 0 1) {u : ℝ} (hu : 0 ≤ u) :
    ∫ (t : ℝ) in 0..u, rightSlope b t = min (min u ((2 * u + b) / 4)) (1 / 2)

    ∫₀ᵘ p_b = min {u, (2u + b)/4, 1/2} for u ≥ 0 and b ∈ [0,1].

    The median section A_b of equation (5.5), as an element of S.

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      The two-branch copula R_b of equation (5.5): the maximal completion of A_b.

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        theorem Papers.OrendayLaresRockel2026XiBeta.rightSection_A {b : ℝ} (hb : b ∈ Set.Icc 0 1) {u : ℝ} (hu : 0 ≤ u) :
        (rightSection b hb).A u = min (min u ((2 * u + b) / 4)) (1 / 2)
        theorem Papers.OrendayLaresRockel2026XiBeta.rightSection_gap {b : ℝ} (hb : b ∈ Set.Icc 0 1) {u : ℝ} (hu : 0 ≤ u) :
        (rightSection b hb).gap u = max |u - 1 / 2| ((1 - b) / 2)
        theorem Papers.OrendayLaresRockel2026XiBeta.Rb_cdf_half {b : ℝ} (hb : b ∈ Set.Icc 0 1) (u : ↑unitInterval) :
        (Rb b hb).cdf ![u, ProbabilityTheory.Copula.unitHalf] = min (min (↑u) ((2 * ↑u + b) / 4)) (1 / 2)